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2112140344115 = 54110411027703
BaseRepresentation
bin11110101111000101010…
…111111111101100110011
321110220210200200120111102
4132233011113333230303
5234101130412002430
64254145345435015
7305411543462564
oct36570527775463
97426720616442
102112140344115
1174483218512a
122a141b63ba6b
13124235306489
147432a02216b
1539e1ce5b345
hex1ebc55ffb33

2112140344115 has 8 divisors (see below), whose sum is σ = 2534577045408. Its totient is φ = 1689706520320.

The previous prime is 2112140344091. The next prime is 2112140344199. The reversal of 2112140344115 is 5114430412112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2112140344115 - 236 = 2043420867379 is a prime.

It is a super-2 number, since 2×21121403441152 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1541354 + ... + 2569056.

It is an arithmetic number, because the mean of its divisors is an integer number (316822130676).

Almost surely, 22112140344115 is an apocalyptic number.

2112140344115 is a deficient number, since it is larger than the sum of its proper divisors (422436701293).

2112140344115 is a wasteful number, since it uses less digits than its factorization.

2112140344115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1438749.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 2112140344115 its reverse (5114430412112), we get a palindrome (7226570756227).

The spelling of 2112140344115 in words is "two trillion, one hundred twelve billion, one hundred forty million, three hundred forty-four thousand, one hundred fifteen".

Divisors: 1 5 411041 1027703 2055205 5138515 422428068823 2112140344115