Base | Representation |
---|---|
bin | 11110101111000101011… |
… | …010101000001010001100 |
3 | 21110220210201222122000022 |
4 | 132233011122220022030 |
5 | 234101131101042444 |
6 | 4254145412321312 |
7 | 305411552365352 |
oct | 36570532501214 |
9 | 7426721878008 |
10 | 2112141034124 |
11 | 744832606590 |
12 | 2a141b913238 |
13 | 1242354b8574 |
14 | 7432a1617d2 |
15 | 39e1d0459ee |
hex | 1ebc56a828c |
2112141034124 has 24 divisors (see below), whose sum is σ = 4052737635408. Its totient is φ = 955190680640.
The previous prime is 2112141034123. The next prime is 2112141034147. The reversal of 2112141034124 is 4214301412112.
It is a super-2 number, since 2×21121410341242 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112141034093 and 2112141034102.
It is not an unprimeable number, because it can be changed into a prime (2112141034123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 121826879 + ... + 121844214.
It is an arithmetic number, because the mean of its divisors is an integer number (168864068142).
Almost surely, 22112141034124 is an apocalyptic number.
It is an amenable number.
2112141034124 is a deficient number, since it is larger than the sum of its proper divisors (1940596601284).
2112141034124 is a wasteful number, since it uses less digits than its factorization.
2112141034124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243671305 (or 243671303 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 2112141034124 its reverse (4214301412112), we get a palindrome (6326442446236).
The spelling of 2112141034124 in words is "two trillion, one hundred twelve billion, one hundred forty-one million, thirty-four thousand, one hundred twenty-four".
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