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21121422151 = 163129579277
BaseRepresentation
bin10011101010111011…
…110101001101000111
32000111222200102020111
4103222323311031013
5321224041002101
613411505213451
71345260061144
oct235273651507
960458612214
1021121422151
118a59546095
124115631287
131cb7b1913b
1410451dd3cb
15839434251
hex4eaef5347

21121422151 has 4 divisors (see below), whose sum is σ = 21251001592. Its totient is φ = 20991842712.

The previous prime is 21121422131. The next prime is 21121422163. The reversal of 21121422151 is 15122412112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21121422151 is a prime.

It is a super-2 number, since 2×211214221512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21121422131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64789476 + ... + 64789801.

It is an arithmetic number, because the mean of its divisors is an integer number (5312750398).

Almost surely, 221121422151 is an apocalyptic number.

21121422151 is a deficient number, since it is larger than the sum of its proper divisors (129579441).

21121422151 is a wasteful number, since it uses less digits than its factorization.

21121422151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129579440.

The product of its digits is 320, while the sum is 22.

Adding to 21121422151 its reverse (15122412112), we get a palindrome (36243834263).

The spelling of 21121422151 in words is "twenty-one billion, one hundred twenty-one million, four hundred twenty-two thousand, one hundred fifty-one".

Divisors: 1 163 129579277 21121422151