Base | Representation |
---|---|
bin | 1001100110101101111000… |
… | …11010110000101010110111 |
3 | 2202210012022201102002022102 |
4 | 10303112330122300222313 |
5 | 10232023330410414020 |
6 | 112531031251452315 |
7 | 4306656561012530 |
oct | 463267432605267 |
9 | 82705281362272 |
10 | 21121515326135 |
11 | 6803647845aa4 |
12 | 24515a88b709b |
13 | ba299a693b03 |
14 | 530402d7d687 |
15 | 269644628475 |
hex | 1335bc6b0ab7 |
21121515326135 has 32 divisors (see below), whose sum is σ = 29399635929600. Its totient is φ = 14266841162112.
The previous prime is 21121515326117. The next prime is 21121515326137. The reversal of 21121515326135 is 53162351512112.
It is not a de Polignac number, because 21121515326135 - 218 = 21121515063991 is a prime.
It is a super-2 number, since 2×211215153261352 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21121515326137) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 164242841 + ... + 164371389.
It is an arithmetic number, because the mean of its divisors is an integer number (918738622800).
Almost surely, 221121515326135 is an apocalyptic number.
21121515326135 is a deficient number, since it is larger than the sum of its proper divisors (8278120603465).
21121515326135 is a wasteful number, since it uses less digits than its factorization.
21121515326135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 198695.
The product of its digits is 54000, while the sum is 38.
Adding to 21121515326135 its reverse (53162351512112), we get a palindrome (74283866838247).
The spelling of 21121515326135 in words is "twenty-one trillion, one hundred twenty-one billion, five hundred fifteen million, three hundred twenty-six thousand, one hundred thirty-five".
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