Base | Representation |
---|---|
bin | 11110101111001000111… |
… | …100010111111010000011 |
3 | 21110220221212100011221011 |
4 | 132233020330113322003 |
5 | 234101241223241344 |
6 | 4254155324541351 |
7 | 305413201400035 |
oct | 36571074277203 |
9 | 7426855304834 |
10 | 2112200212099 |
11 | 744862a558aa |
12 | 2a14376b1857 |
13 | 124244838313 |
14 | 74333d67c55 |
15 | 39e23334d34 |
hex | 1ebc8f17e83 |
2112200212099 has 2 divisors, whose sum is σ = 2112200212100. Its totient is φ = 2112200212098.
The previous prime is 2112200212097. The next prime is 2112200212121. The reversal of 2112200212099 is 9902120022112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2112200212099 - 21 = 2112200212097 is a prime.
It is a super-2 number, since 2×21122002120992 (a number of 25 digits) contains 22 as substring.
Together with 2112200212097, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 2112200212099.
It is not a weakly prime, because it can be changed into another prime (2112200212093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056100106049 + 1056100106050.
It is an arithmetic number, because the mean of its divisors is an integer number (1056100106050).
Almost surely, 22112200212099 is an apocalyptic number.
2112200212099 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112200212099 is an equidigital number, since it uses as much as digits as its factorization.
2112200212099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 2112200212099 in words is "two trillion, one hundred twelve billion, two hundred million, two hundred twelve thousand, ninety-nine".
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