Search a number
-
+
211221000217 is a prime number
BaseRepresentation
bin1100010010110111000…
…0001011000000011001
3202012012100120120001001
43010231300023000121
511430040034001332
6241011131025001
721155152610233
oct3045560130031
9665170516031
10211221000217
118163a8257a7
1234b2959b161
1316bc1c74586
14a31a47d253
15576361a0e7
hex312dc0b019

211221000217 has 2 divisors, whose sum is σ = 211221000218. Its totient is φ = 211221000216.

The previous prime is 211221000203. The next prime is 211221000253. The reversal of 211221000217 is 712000122112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 206251314201 + 4969686016 = 454149^2 + 70496^2 .

It is a cyclic number.

It is not a de Polignac number, because 211221000217 - 223 = 211212611609 is a prime.

It is a super-2 number, since 2×2112210002172 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211221000194 and 211221000203.

It is not a weakly prime, because it can be changed into another prime (211221000017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610500108 + 105610500109.

It is an arithmetic number, because the mean of its divisors is an integer number (105610500109).

Almost surely, 2211221000217 is an apocalyptic number.

It is an amenable number.

211221000217 is a deficient number, since it is larger than the sum of its proper divisors (1).

211221000217 is an equidigital number, since it uses as much as digits as its factorization.

211221000217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 19.

Adding to 211221000217 its reverse (712000122112), we get a palindrome (923221122329).

The spelling of 211221000217 in words is "two hundred eleven billion, two hundred twenty-one million, two hundred seventeen", and thus it is an aban number.