Base | Representation |
---|---|
bin | 1100010010110111000… |
… | …0001011000000001011 |
3 | 202012012100120120000112 |
4 | 3010231300023000023 |
5 | 11430040034001303 |
6 | 241011131024535 |
7 | 21155152610213 |
oct | 3045560130013 |
9 | 665170516015 |
10 | 211221000203 |
11 | 8163a825794 |
12 | 34b2959b14b |
13 | 16bc1c74575 |
14 | a31a47d243 |
15 | 576361a0d8 |
hex | 312dc0b00b |
211221000203 has 2 divisors, whose sum is σ = 211221000204. Its totient is φ = 211221000202.
The previous prime is 211221000161. The next prime is 211221000217. The reversal of 211221000203 is 302000122112.
It is a happy number.
It is an a-pointer prime, because the next prime (211221000217) can be obtained adding 211221000203 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211221000203 - 230 = 210147258379 is a prime.
It is a super-2 number, since 2×2112210002032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211221000253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610500101 + 105610500102.
It is an arithmetic number, because the mean of its divisors is an integer number (105610500102).
Almost surely, 2211221000203 is an apocalyptic number.
211221000203 is a deficient number, since it is larger than the sum of its proper divisors (1).
211221000203 is an equidigital number, since it uses as much as digits as its factorization.
211221000203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 211221000203 its reverse (302000122112), we get a palindrome (513221122315).
The spelling of 211221000203 in words is "two hundred eleven billion, two hundred twenty-one million, two hundred three", and thus it is an aban number.
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