Base | Representation |
---|---|
bin | 11110101111001001100… |
… | …010001011010110110111 |
3 | 21110220222112222122222201 |
4 | 132233021202023112313 |
5 | 234101301242402132 |
6 | 4254200321205331 |
7 | 305413351543255 |
oct | 36571142132667 |
9 | 7426875878881 |
10 | 2112210122167 |
11 | 744868604442 |
12 | 2a143aa90847 |
13 | 1242468c7c72 |
14 | 743353c75d5 |
15 | 39e241412e7 |
hex | 1ebc988b5b7 |
2112210122167 has 2 divisors, whose sum is σ = 2112210122168. Its totient is φ = 2112210122166.
The previous prime is 2112210122053. The next prime is 2112210122177. The reversal of 2112210122167 is 7612210122112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112210122167 - 27 = 2112210122039 is a prime.
It is a super-2 number, since 2×21122101221672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112210122177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056105061083 + 1056105061084.
It is an arithmetic number, because the mean of its divisors is an integer number (1056105061084).
Almost surely, 22112210122167 is an apocalyptic number.
2112210122167 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112210122167 is an equidigital number, since it uses as much as digits as its factorization.
2112210122167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 2112210122167 its reverse (7612210122112), we get a palindrome (9724420244279).
Subtracting 2112210122167 from its reverse (7612210122112), we obtain a palindrome (5499999999945).
The spelling of 2112210122167 in words is "two trillion, one hundred twelve billion, two hundred ten million, one hundred twenty-two thousand, one hundred sixty-seven".
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