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211221102017 is a prime number
BaseRepresentation
bin1100010010110111000…
…0100011110111000001
3202012012100202201200102
43010231300203313001
511430040100231032
6241011133132145
721155153513102
oct3045560436701
9665170681612
10211221102017
118163a895232
1234b2962a055
1316bc1caba03
14a31a4a83a9
15576363a362
hex312dc23dc1

211221102017 has 2 divisors, whose sum is σ = 211221102018. Its totient is φ = 211221102016.

The previous prime is 211221102007. The next prime is 211221102067. The reversal of 211221102017 is 710201122112.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 151215210496 + 60005891521 = 388864^2 + 244961^2 .

It is a cyclic number.

It is not a de Polignac number, because 211221102017 - 212 = 211221097921 is a prime.

It is a super-2 number, since 2×2112211020172 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211221102017.

It is not a weakly prime, because it can be changed into another prime (211221102007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610551008 + 105610551009.

It is an arithmetic number, because the mean of its divisors is an integer number (105610551009).

Almost surely, 2211221102017 is an apocalyptic number.

It is an amenable number.

211221102017 is a deficient number, since it is larger than the sum of its proper divisors (1).

211221102017 is an equidigital number, since it uses as much as digits as its factorization.

211221102017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 211221102017 its reverse (710201122112), we get a palindrome (921422224129).

The spelling of 211221102017 in words is "two hundred eleven billion, two hundred twenty-one million, one hundred two thousand, seventeen".