Base | Representation |
---|---|
bin | 11110101111001001100… |
… | …110010010110010110011 |
3 | 21110220222122000111011000 |
4 | 132233021212102302303 |
5 | 234101302031414303 |
6 | 4254200400253043 |
7 | 305413363656165 |
oct | 36571146226263 |
9 | 7426878014130 |
10 | 2112211201203 |
11 | 744869181104 |
12 | 2a143b311183 |
13 | 124246bb514c |
14 | 743355c8935 |
15 | 39e242a5da3 |
hex | 1ebc9992cb3 |
2112211201203 has 16 divisors (see below), whose sum is σ = 3237105290400. Its totient is φ = 1359584220960.
The previous prime is 2112211201183. The next prime is 2112211201207. The reversal of 2112211201203 is 3021021122112.
It is not a de Polignac number, because 2112211201203 - 25 = 2112211201171 is a prime.
It is a super-2 number, since 2×21122112012032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2112211201207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1348793088 + ... + 1348794653.
It is an arithmetic number, because the mean of its divisors is an integer number (202319080650).
Almost surely, 22112211201203 is an apocalyptic number.
2112211201203 is a deficient number, since it is larger than the sum of its proper divisors (1124894089197).
2112211201203 is a wasteful number, since it uses less digits than its factorization.
2112211201203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2697587779 (or 2697587773 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 2112211201203 its reverse (3021021122112), we get a palindrome (5133232323315).
The spelling of 2112211201203 in words is "two trillion, one hundred twelve billion, two hundred eleven million, two hundred one thousand, two hundred three".
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