Base | Representation |
---|---|
bin | 11110101111001001100… |
… | …110010010110010110111 |
3 | 21110220222122000111011011 |
4 | 132233021212102302313 |
5 | 234101302031414312 |
6 | 4254200400253051 |
7 | 305413363656202 |
oct | 36571146226267 |
9 | 7426878014134 |
10 | 2112211201207 |
11 | 744869181108 |
12 | 2a143b311187 |
13 | 124246bb5153 |
14 | 743355c8939 |
15 | 39e242a5da7 |
hex | 1ebc9992cb7 |
2112211201207 has 2 divisors, whose sum is σ = 2112211201208. Its totient is φ = 2112211201206.
The previous prime is 2112211201183. The next prime is 2112211201253. The reversal of 2112211201207 is 7021021122112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2112211201207 - 235 = 2077851462839 is a prime.
It is a super-2 number, since 2×21122112012072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112212201207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056105600603 + 1056105600604.
It is an arithmetic number, because the mean of its divisors is an integer number (1056105600604).
Almost surely, 22112211201207 is an apocalyptic number.
2112211201207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112211201207 is an equidigital number, since it uses as much as digits as its factorization.
2112211201207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 2112211201207 its reverse (7021021122112), we get a palindrome (9133232323319).
The spelling of 2112211201207 in words is "two trillion, one hundred twelve billion, two hundred eleven million, two hundred one thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •