Search a number
-
+
21122112099997 is a prime number
BaseRepresentation
bin1001100110101110111111…
…11111010001011010011101
32202210020212022100100011001
410303113133333101122131
510232031041144144442
6112531210410430301
74310010425344156
oct463273777213235
982706768310131
1021122112099997
1168039236a0037
122451734732391
13ba2a6420013c
1453045c32692d
1526967bc0a2b7
hex1335dffd169d

21122112099997 has 2 divisors, whose sum is σ = 21122112099998. Its totient is φ = 21122112099996.

The previous prime is 21122112099961. The next prime is 21122112100027. The reversal of 21122112099997 is 79999021122112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21030533840836 + 91578259161 = 4585906^2 + 302619^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21122112099997 is a prime.

It is a super-2 number, since 2×211221120999972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21122112096997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561056049998 + 10561056049999.

It is an arithmetic number, because the mean of its divisors is an integer number (10561056049999).

Almost surely, 221122112099997 is an apocalyptic number.

It is an amenable number.

21122112099997 is a deficient number, since it is larger than the sum of its proper divisors (1).

21122112099997 is an equidigital number, since it uses as much as digits as its factorization.

21122112099997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 734832, while the sum is 55.

The spelling of 21122112099997 in words is "twenty-one trillion, one hundred twenty-two billion, one hundred twelve million, ninety-nine thousand, nine hundred ninety-seven".