Base | Representation |
---|---|
bin | 1100010010110111000… |
… | …0101011010000101011 |
3 | 202012012100211021021011 |
4 | 3010231300223100223 |
5 | 11430040102213311 |
6 | 241011133524351 |
7 | 21155154000346 |
oct | 3045560532053 |
9 | 665170737234 |
10 | 211221132331 |
11 | 8163a905a90 |
12 | 34b296436b7 |
13 | 16bc1cbc751 |
14 | a31a4b545d |
15 | 5763644321 |
hex | 312dc2b42b |
211221132331 has 4 divisors (see below), whose sum is σ = 230423053464. Its totient is φ = 192019211200.
The previous prime is 211221132329. The next prime is 211221132371. The reversal of 211221132331 is 133231122112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211221132331 - 21 = 211221132329 is a prime.
It is a super-2 number, since 2×2112211323312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211221132371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9600960550 + ... + 9600960571.
It is an arithmetic number, because the mean of its divisors is an integer number (57605763366).
Almost surely, 2211221132331 is an apocalyptic number.
211221132331 is a deficient number, since it is larger than the sum of its proper divisors (19201921133).
211221132331 is a wasteful number, since it uses less digits than its factorization.
211221132331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19201921132.
The product of its digits is 432, while the sum is 22.
Adding to 211221132331 its reverse (133231122112), we get a palindrome (344452254443).
The spelling of 211221132331 in words is "two hundred eleven billion, two hundred twenty-one million, one hundred thirty-two thousand, three hundred thirty-one".
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