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211221201312133 = 3731107151149551
BaseRepresentation
bin110000000001101011000100…
…101011000101100110000101
31000200212112211200120200001221
4300001223010223011212011
5210141122010013442013
62025121402540520341
762330141162603605
oct6001530453054605
91020775750520057
10211221201312133
1161335454685021
121b834100b500b1
1390b20c62404bc
143a23236d14c05
15196453513308d
hexc01ac4ac5985

211221201312133 has 8 divisors (see below), whose sum is σ = 211806612064256. Its totient is φ = 210635892882000.

The previous prime is 211221201312109. The next prime is 211221201312169. The reversal of 211221201312133 is 331213102122112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211221201312133 is a prime.

It is a super-2 number, since 2×2112212013121332 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211221201312098 and 211221201312107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211221201312533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21445293 + ... + 29704258.

It is an arithmetic number, because the mean of its divisors is an integer number (26475826508032).

Almost surely, 2211221201312133 is an apocalyptic number.

It is an amenable number.

211221201312133 is a deficient number, since it is larger than the sum of its proper divisors (585410752123).

211221201312133 is a wasteful number, since it uses less digits than its factorization.

211221201312133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51160995.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 211221201312133 its reverse (331213102122112), we get a palindrome (542434303434245).

The spelling of 211221201312133 in words is "two hundred eleven trillion, two hundred twenty-one billion, two hundred one million, three hundred twelve thousand, one hundred thirty-three".

Divisors: 1 373 11071 4129483 51149551 19078782523 566276679121 211221201312133