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21122133132 = 2231760177761
BaseRepresentation
bin10011101010111110…
…100010110010001100
32000112001000112112010
4103222332202302030
5321224231230012
613411532341220
71345266112032
oct235276426214
960461015463
1021122133132
118a59991281
124115914810
131cb8007939
141045346552
15839524c3c
hex4eafa2c8c

21122133132 has 12 divisors (see below), whose sum is σ = 49284977336. Its totient is φ = 7040711040.

The previous prime is 21122133127. The next prime is 21122133181. The reversal of 21122133132 is 23133122112.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-5 number, since 5×211221331325 (a number of 53 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 21122133099 and 21122133108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 880088869 + ... + 880088892.

Almost surely, 221122133132 is an apocalyptic number.

It is an amenable number.

21122133132 is an abundant number, since it is smaller than the sum of its proper divisors (28162844204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21122133132 is a wasteful number, since it uses less digits than its factorization.

21122133132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1760177768 (or 1760177766 counting only the distinct ones).

The product of its digits is 432, while the sum is 21.

Adding to 21122133132 its reverse (23133122112), we get a palindrome (44255255244).

The spelling of 21122133132 in words is "twenty-one billion, one hundred twenty-two million, one hundred thirty-three thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 1760177761 3520355522 5280533283 7040711044 10561066566 21122133132