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211222221219983 is a prime number
BaseRepresentation
bin110000000001101100000001…
…011101101110100010001111
31000200212122110202201100121202
4300001230001131232202033
5210141131102113014413
62025122052053020115
762330205355641101
oct6001540135564217
91020778422640552
10211222221219983
1161335928365976
121b83434662463b
1390b222962ab7c
143a232d2565571
151964594947e58
hexc01b0176e88f

211222221219983 has 2 divisors, whose sum is σ = 211222221219984. Its totient is φ = 211222221219982.

The previous prime is 211222221219959. The next prime is 211222221220013. The reversal of 211222221219983 is 389912122222112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211222221219983 - 210 = 211222221218959 is a prime.

It is a super-3 number, since 3×2112222212199833 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211212221219983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611110609991 + 105611110609992.

It is an arithmetic number, because the mean of its divisors is an integer number (105611110609992).

Almost surely, 2211222221219983 is an apocalyptic number.

211222221219983 is a deficient number, since it is larger than the sum of its proper divisors (1).

211222221219983 is an equidigital number, since it uses as much as digits as its factorization.

211222221219983 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 248832, while the sum is 47.

The spelling of 211222221219983 in words is "two hundred eleven trillion, two hundred twenty-two billion, two hundred twenty-one million, two hundred nineteen thousand, nine hundred eighty-three".