2112224140217 has 2 divisors, whose sum is σ = 2112224140218. Its totient is φ = 2112224140216.

The previous prime is 2112224140181. The next prime is 2112224140253. The reversal of 2112224140217 is 7120414222112.

It is a balanced prime because it is at equal distance from previous prime (2112224140181) and next prime (2112224140253).

It can be written as a sum of positive squares in only one way, i.e., 1457582948416 + 654641191801 = 1207304^2 + 809099^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112224140217 - 2¹⁸ = 2112223878073 is a prime.

It is a super-3 number, since 3×2112224140217³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 2112224140217.

It is not a weakly prime, because it can be changed into another prime (2112224140717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056112070108 + 1056112070109.

It is an arithmetic number, because the mean of its divisors is an integer number (1056112070109).

Almost surely, 2^{2112224140217} is an apocalyptic number.

It is an amenable number.

2112224140217 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112224140217 is an equidigital number, since it uses as much as digits as its factorization.

2112224140217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3584, while the sum is 29.

Adding to 2112224140217 its reverse (7120414222112), we get a palindrome (9232638362329).

The spelling of 2112224140217 in words is "two trillion, one hundred twelve billion, two hundred twenty-four million, one hundred forty thousand, two hundred seventeen".