Base | Representation |
---|---|
bin | 11110101111001011111… |
… | …011100110001111100111 |
3 | 21110221002100122221221012 |
4 | 132233023323212033213 |
5 | 234101342041342302 |
6 | 4254204315212435 |
7 | 305414350440341 |
oct | 36571373461747 |
9 | 7427070587835 |
10 | 2112250340327 |
11 | 744889283996 |
12 | 2a145044711b |
13 | 124252039baa |
14 | 7433a896291 |
15 | 39e27937a52 |
hex | 1ebcbee63e7 |
2112250340327 has 2 divisors, whose sum is σ = 2112250340328. Its totient is φ = 2112250340326.
The previous prime is 2112250340287. The next prime is 2112250340353. The reversal of 2112250340327 is 7230430522112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112250340327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2112250340293 and 2112250340302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112250300327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056125170163 + 1056125170164.
It is an arithmetic number, because the mean of its divisors is an integer number (1056125170164).
Almost surely, 22112250340327 is an apocalyptic number.
2112250340327 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112250340327 is an equidigital number, since it uses as much as digits as its factorization.
2112250340327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 2112250340327 its reverse (7230430522112), we get a palindrome (9342680862439).
The spelling of 2112250340327 in words is "two trillion, one hundred twelve billion, two hundred fifty million, three hundred forty thousand, three hundred twenty-seven".
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