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2112303314003 = 19991056679997
BaseRepresentation
bin11110101111001111000…
…101101011010001010011
321110221020001100022011012
4132233033011223101103
5234101444122022003
64254213450441135
7305415562631501
oct36571705532123
97427201308135
102112303314003
11744906175893
122a14661331ab
1312425ccc696c
1474343925671
1539e2c3ed8d8
hex1ebcf16b453

2112303314003 has 4 divisors (see below), whose sum is σ = 2113359996000. Its totient is φ = 2111246632008.

The previous prime is 2112303313957. The next prime is 2112303314053. The reversal of 2112303314003 is 3004133032112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2112303314003 - 210 = 2112303312979 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2112303314003.

It is not an unprimeable number, because it can be changed into a prime (2112303314053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 528338000 + ... + 528341997.

It is an arithmetic number, because the mean of its divisors is an integer number (528339999000).

Almost surely, 22112303314003 is an apocalyptic number.

2112303314003 is a deficient number, since it is larger than the sum of its proper divisors (1056681997).

2112303314003 is a wasteful number, since it uses less digits than its factorization.

2112303314003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1056681996.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2112303314003 its reverse (3004133032112), we get a palindrome (5116436346115).

The spelling of 2112303314003 in words is "two trillion, one hundred twelve billion, three hundred three million, three hundred fourteen thousand, three".

Divisors: 1 1999 1056679997 2112303314003