Base | Representation |
---|---|
bin | 1100010010111001011… |
… | …0110001101100010111 |
3 | 202012020001121200222102 |
4 | 3010232112301230113 |
5 | 11430100131321101 |
6 | 241012131552315 |
7 | 21155334616352 |
oct | 3045626615427 |
9 | 665201550872 |
10 | 211231120151 |
11 | 81645507a87 |
12 | 34b30a5b69b |
13 | 16bc40a88bc |
14 | a31b955299 |
15 | 576446886b |
hex | 312e5b1b17 |
211231120151 has 2 divisors, whose sum is σ = 211231120152. Its totient is φ = 211231120150.
The previous prime is 211231120021. The next prime is 211231120211. The reversal of 211231120151 is 151021132112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211231120151 is a prime.
It is a super-2 number, since 2×2112311201512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211231120351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105615560075 + 105615560076.
It is an arithmetic number, because the mean of its divisors is an integer number (105615560076).
Almost surely, 2211231120151 is an apocalyptic number.
211231120151 is a deficient number, since it is larger than the sum of its proper divisors (1).
211231120151 is an equidigital number, since it uses as much as digits as its factorization.
211231120151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 211231120151 its reverse (151021132112), we get a palindrome (362252252263).
The spelling of 211231120151 in words is "two hundred eleven billion, two hundred thirty-one million, one hundred twenty thousand, one hundred fifty-one".
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