Base | Representation |
---|---|
bin | 110000000001110100100000… |
… | …011101010001111011111011 |
3 | 1000200220111222122121210101100 |
4 | 300001310200131101323323 |
5 | 210141303231232144011 |
6 | 2025130200042022443 |
7 | 62330650204623603 |
oct | 6001644035217373 |
9 | 1020814878553340 |
10 | 211231331131131 |
11 | 613397826a7a63 |
12 | 1b8360694a7a23 |
13 | 90b304bab1c3c |
14 | 3a239183cbc03 |
15 | 19649295d5d56 |
hex | c01d20751efb |
211231331131131 has 24 divisors (see below), whose sum is σ = 314027322695424. Its totient is φ = 136765293199920.
The previous prime is 211231331131127. The next prime is 211231331131201. The reversal of 211231331131131 is 131131133132112.
211231331131131 is a `hidden beast` number, since 2 + 1 + 1 + 2 + 3 + 1 + 3 + 311 + 311 + 31 = 666.
It is not a de Polignac number, because 211231331131131 - 22 = 211231331131127 is a prime.
It is a super-2 number, since 2×2112313311311312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211231331131095 and 211231331131104.
It is not an unprimeable number, because it can be changed into a prime (211231331133131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2466863631 + ... + 2466949256.
It is an arithmetic number, because the mean of its divisors is an integer number (13084471778976).
Almost surely, 2211231331131131 is an apocalyptic number.
211231331131131 is a deficient number, since it is larger than the sum of its proper divisors (102795991564293).
211231331131131 is a wasteful number, since it uses less digits than its factorization.
211231331131131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4933813031 (or 4933813028 counting only the distinct ones).
The product of its digits is 972, while the sum is 27.
Adding to 211231331131131 its reverse (131131133132112), we get a palindrome (342362464263243).
It can be divided in two parts, 21123133113 and 1131, that added together give a square (21123134244 = 1453382).
The spelling of 211231331131131 in words is "two hundred eleven trillion, two hundred thirty-one billion, three hundred thirty-one million, one hundred thirty-one thousand, one hundred thirty-one".
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