Base | Representation |
---|---|
bin | 11110101111001111101… |
… | …110110101100101000101 |
3 | 21110221020210122111102122 |
4 | 132233033232311211011 |
5 | 234102004402313013 |
6 | 4254214514015325 |
7 | 305416053431552 |
oct | 36571756654505 |
9 | 7427223574378 |
10 | 2112314104133 |
11 | 744911275652 |
12 | 2a1469877545 |
13 | 12426230405c |
14 | 74345133a29 |
15 | 39e2d330a08 |
hex | 1ebcfbb5945 |
2112314104133 has 2 divisors, whose sum is σ = 2112314104134. Its totient is φ = 2112314104132.
The previous prime is 2112314104099. The next prime is 2112314104139. The reversal of 2112314104133 is 3314014132112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1485237002209 + 627077101924 = 1218703^2 + 791882^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112314104133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112314104139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056157052066 + 1056157052067.
It is an arithmetic number, because the mean of its divisors is an integer number (1056157052067).
Almost surely, 22112314104133 is an apocalyptic number.
It is an amenable number.
2112314104133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112314104133 is an equidigital number, since it uses as much as digits as its factorization.
2112314104133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 2112314104133 its reverse (3314014132112), we get a palindrome (5426328236245).
The spelling of 2112314104133 in words is "two trillion, one hundred twelve billion, three hundred fourteen million, one hundred four thousand, one hundred thirty-three".
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