2112411432031 has 2 divisors, whose sum is σ = 2112411432032. Its totient is φ = 2112411432030.

The previous prime is 2112411432013. The next prime is 2112411432041. The reversal of 2112411432031 is 1302341142112.

Together with previous prime (2112411432013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2112411432031 - 2²³ = 2112403043423 is a prime.

It is a super-2 number, since 2×2112411432031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2112411431987 and 2112411432005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112411432041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056205716015 + 1056205716016.

It is an arithmetic number, because the mean of its divisors is an integer number (1056205716016).

Almost surely, 2^{2112411432031} is an apocalyptic number.

2112411432031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112411432031 is an equidigital number, since it uses as much as digits as its factorization.

2112411432031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2112411432031 its reverse (1302341142112), we get a palindrome (3414752574143).

The spelling of 2112411432031 in words is "two trillion, one hundred twelve billion, four hundred eleven million, four hundred thirty-two thousand, thirty-one".