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211241420023 is a prime number
BaseRepresentation
bin1100010010111011111…
…0000100010011110111
3202012020202222222202011
43010232332010103313
511430110300420043
6241013140425051
721155521305214
oct3045676042367
9665222888664
10211241420023
1181650302477
1234b343a8187
1316bc6273aba
14a31d076b0b
15576530059d
hex312ef844f7

211241420023 has 2 divisors, whose sum is σ = 211241420024. Its totient is φ = 211241420022.

The previous prime is 211241419997. The next prime is 211241420051. The reversal of 211241420023 is 320024142112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211241420023 - 233 = 202651485431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211241419976 and 211241420003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211241421023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105620710011 + 105620710012.

It is an arithmetic number, because the mean of its divisors is an integer number (105620710012).

Almost surely, 2211241420023 is an apocalyptic number.

211241420023 is a deficient number, since it is larger than the sum of its proper divisors (1).

211241420023 is an equidigital number, since it uses as much as digits as its factorization.

211241420023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 211241420023 its reverse (320024142112), we get a palindrome (531265562135).

The spelling of 211241420023 in words is "two hundred eleven billion, two hundred forty-one million, four hundred twenty thousand, twenty-three".