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211242441281 is a prime number
BaseRepresentation
bin1100010010111100000…
…1111101101001000001
3202012020211220212122112
43010233001331221001
511430111031110111
6241013214345105
721155533060514
oct3045701755101
9665224825575
10211242441281
118165093a793
1234b347bb195
1316bc65408b1
14a31d260d7b
155765452e8b
hex312f07da41

211242441281 has 2 divisors, whose sum is σ = 211242441282. Its totient is φ = 211242441280.

The previous prime is 211242441229. The next prime is 211242441317. The reversal of 211242441281 is 182144242112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138603567025 + 72638874256 = 372295^2 + 269516^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211242441281 is a prime.

It is a super-2 number, since 2×2112424412812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211242441581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105621220640 + 105621220641.

It is an arithmetic number, because the mean of its divisors is an integer number (105621220641).

Almost surely, 2211242441281 is an apocalyptic number.

It is an amenable number.

211242441281 is a deficient number, since it is larger than the sum of its proper divisors (1).

211242441281 is an equidigital number, since it uses as much as digits as its factorization.

211242441281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8192, while the sum is 32.

Adding to 211242441281 its reverse (182144242112), we get a palindrome (393386683393).

The spelling of 211242441281 in words is "two hundred eleven billion, two hundred forty-two million, four hundred forty-one thousand, two hundred eighty-one".