Base | Representation |
---|---|
bin | 1100010010111100000… |
… | …1111101101001100101 |
3 | 202012020211220212200212 |
4 | 3010233001331221211 |
5 | 11430111031110232 |
6 | 241013214345205 |
7 | 21155533060565 |
oct | 3045701755145 |
9 | 665224825625 |
10 | 211242441317 |
11 | 8165093a816 |
12 | 34b347bb205 |
13 | 16bc654090b |
14 | a31d260da5 |
15 | 5765452eb2 |
hex | 312f07da65 |
211242441317 has 2 divisors, whose sum is σ = 211242441318. Its totient is φ = 211242441316.
The previous prime is 211242441281. The next prime is 211242441343. The reversal of 211242441317 is 713144242112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 137013983716 + 74228457601 = 370154^2 + 272449^2 .
It is a cyclic number.
It is not a de Polignac number, because 211242441317 - 218 = 211242179173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211242401317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105621220658 + 105621220659.
It is an arithmetic number, because the mean of its divisors is an integer number (105621220659).
Almost surely, 2211242441317 is an apocalyptic number.
It is an amenable number.
211242441317 is a deficient number, since it is larger than the sum of its proper divisors (1).
211242441317 is an equidigital number, since it uses as much as digits as its factorization.
211242441317 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10752, while the sum is 32.
Adding to 211242441317 its reverse (713144242112), we get a palindrome (924386683429).
The spelling of 211242441317 in words is "two hundred eleven billion, two hundred forty-two million, four hundred forty-one thousand, three hundred seventeen".
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