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211244234053 = 217999690547
BaseRepresentation
bin1100010010111100100…
…0110011010101000101
3202012020222021221212111
43010233020303111011
511430112010442203
6241013321021021
721155554235326
oct3045710632505
9665228257774
10211244234053
1181651954716
1234b35324771
1316bc6a1a8c8
14a31d5aa44d
1557656a926d
hex312f233545

211244234053 has 4 divisors (see below), whose sum is σ = 211253946400. Its totient is φ = 211234521708.

The previous prime is 211244234029. The next prime is 211244234081. The reversal of 211244234053 is 350432442112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211244234053 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211244234083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4823475 + ... + 4867072.

It is an arithmetic number, because the mean of its divisors is an integer number (52813486600).

Almost surely, 2211244234053 is an apocalyptic number.

It is an amenable number.

211244234053 is a deficient number, since it is larger than the sum of its proper divisors (9712347).

211244234053 is an equidigital number, since it uses as much as digits as its factorization.

211244234053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9712346.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 211244234053 its reverse (350432442112), we get a palindrome (561676676165).

The spelling of 211244234053 in words is "two hundred eleven billion, two hundred forty-four million, two hundred thirty-four thousand, fifty-three".

Divisors: 1 21799 9690547 211244234053