Base | Representation |
---|---|
bin | 1100010010111100100… |
… | …0110011010101000101 |
3 | 202012020222021221212111 |
4 | 3010233020303111011 |
5 | 11430112010442203 |
6 | 241013321021021 |
7 | 21155554235326 |
oct | 3045710632505 |
9 | 665228257774 |
10 | 211244234053 |
11 | 81651954716 |
12 | 34b35324771 |
13 | 16bc6a1a8c8 |
14 | a31d5aa44d |
15 | 57656a926d |
hex | 312f233545 |
211244234053 has 4 divisors (see below), whose sum is σ = 211253946400. Its totient is φ = 211234521708.
The previous prime is 211244234029. The next prime is 211244234081. The reversal of 211244234053 is 350432442112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211244234053 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211244234083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4823475 + ... + 4867072.
It is an arithmetic number, because the mean of its divisors is an integer number (52813486600).
Almost surely, 2211244234053 is an apocalyptic number.
It is an amenable number.
211244234053 is a deficient number, since it is larger than the sum of its proper divisors (9712347).
211244234053 is an equidigital number, since it uses as much as digits as its factorization.
211244234053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9712346.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 211244234053 its reverse (350432442112), we get a palindrome (561676676165).
The spelling of 211244234053 in words is "two hundred eleven billion, two hundred forty-four million, two hundred thirty-four thousand, fifty-three".
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