211264331401301 has 2 divisors, whose sum is σ = 211264331401302. Its totient is φ = 211264331401300.

The previous prime is 211264331401243. The next prime is 211264331401327. The reversal of 211264331401301 is 103104133462112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 183442915692100 + 27821415709201 = 13544110^2 + 5274601^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211264331401301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211264331401381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105632165700650 + 105632165700651.

It is an arithmetic number, because the mean of its divisors is an integer number (105632165700651).

Almost surely, 2^{211264331401301} is an apocalyptic number.

It is an amenable number.

211264331401301 is a deficient number, since it is larger than the sum of its proper divisors (1).

211264331401301 is an equidigital number, since it uses as much as digits as its factorization.

211264331401301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 32.

Adding to 211264331401301 its reverse (103104133462112), we get a palindrome (314368464863413).

The spelling of 211264331401301 in words is "two hundred eleven trillion, two hundred sixty-four billion, three hundred thirty-one million, four hundred one thousand, three hundred one".