211264331401339 has 2 divisors, whose sum is σ = 211264331401340. Its totient is φ = 211264331401338.

The previous prime is 211264331401327. The next prime is 211264331401373. The reversal of 211264331401339 is 933104133462112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211264331401339 - 2²⁵ = 211264297846907 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211264331401295 and 211264331401304.

It is not a weakly prime, because it can be changed into another prime (211264331404339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105632165700669 + 105632165700670.

It is an arithmetic number, because the mean of its divisors is an integer number (105632165700670).

Almost surely, 2^{211264331401339} is an apocalyptic number.

211264331401339 is a deficient number, since it is larger than the sum of its proper divisors (1).

211264331401339 is an equidigital number, since it uses as much as digits as its factorization.

211264331401339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 279936, while the sum is 43.

The spelling of 211264331401339 in words is "two hundred eleven trillion, two hundred sixty-four billion, three hundred thirty-one million, four hundred one thousand, three hundred thirty-nine".