21130000033 has 2 divisors, whose sum is σ = 21130000034. Its totient is φ = 21130000032.

The previous prime is 21129999991. The next prime is 21130000037. The reversal of 21130000033 is 33000003112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12156606049 + 8973393984 = 110257^2 + 94728^2 .

It is a cyclic number.

It is not a de Polignac number, because 21130000033 - 2⁹ = 21129999521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21129999968 and 21130000022.

It is not a weakly prime, because it can be changed into another prime (21130000037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565000016 + 10565000017.

It is an arithmetic number, because the mean of its divisors is an integer number (10565000017).

Almost surely, 2^21130000033 is an apocalyptic number.

It is an amenable number.

21130000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

21130000033 is an equidigital number, since it uses as much as digits as its factorization.

21130000033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 21130000033 its reverse (33000003112), we get a palindrome (54130003145).

The spelling of 21130000033 in words is "twenty-one billion, one hundred thirty million, thirty-three", and thus it is an aban number.