Base | Representation |
---|---|
bin | 11001001100000… |
… | …10111101111001 |
3 | 112201121011101222 |
4 | 30212002331321 |
5 | 413043101332 |
6 | 32544521425 |
7 | 5144010422 |
oct | 1446027571 |
9 | 481534358 |
10 | 211300217 |
11 | a9300a87 |
12 | 5a920275 |
13 | 34a1291b |
14 | 200c4649 |
15 | 1383c712 |
hex | c982f79 |
211300217 has 2 divisors, whose sum is σ = 211300218. Its totient is φ = 211300216.
The previous prime is 211300213. The next prime is 211300223. The reversal of 211300217 is 712003112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 156850576 + 54449641 = 12524^2 + 7379^2 .
It is a cyclic number.
It is not a de Polignac number, because 211300217 - 22 = 211300213 is a prime.
It is a super-4 number, since 4×2113002174 (a number of 34 digits) contains 4444 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 211300195 and 211300204.
It is not a weakly prime, because it can be changed into another prime (211300211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105650108 + 105650109.
It is an arithmetic number, because the mean of its divisors is an integer number (105650109).
Almost surely, 2211300217 is an apocalyptic number.
It is an amenable number.
211300217 is a deficient number, since it is larger than the sum of its proper divisors (1).
211300217 is an equidigital number, since it uses as much as digits as its factorization.
211300217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 17.
The square root of 211300217 is about 14536.1692684146. The cubic root of 211300217 is about 595.6164004951.
Adding to 211300217 its reverse (712003112), we get a palindrome (923303329).
The spelling of 211300217 in words is "two hundred eleven million, three hundred thousand, two hundred seventeen".
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