21130041111401 has 4 divisors (see below), whose sum is σ = 21132281608704. Its totient is φ = 21127800614100.

The previous prime is 21130041111397. The next prime is 21130041111409. The reversal of 21130041111401 is 10411114003112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21130041111401 - 2² = 21130041111397 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21130041111409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1120234505 + ... + 1120253366.

It is an arithmetic number, because the mean of its divisors is an integer number (5283070402176).

Almost surely, 2^{21130041111401} is an apocalyptic number.

It is an amenable number.

21130041111401 is a deficient number, since it is larger than the sum of its proper divisors (2240497303).

21130041111401 is an equidigital number, since it uses as much as digits as its factorization.

21130041111401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2240497302.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 21130041111401 its reverse (10411114003112), we get a palindrome (31541155114513).

The spelling of 21130041111401 in words is "twenty-one trillion, one hundred thirty billion, forty-one million, one hundred eleven thousand, four hundred one".