21130044431040 has 672 divisors, whose sum is σ = 77278530288960. Its totient is φ = 5289106636800.

The previous prime is 21130044430987. The next prime is 21130044431059. The reversal of 21130044431040 is 4013444003112.

21130044431040 is a `hidden beast` number, since 2 + 1 + 1 + 300 + 4 + 4 + 4 + 310 + 40 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 21130044430995 and 21130044431013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 5967251670 + ... + 5967255210.

It is an arithmetic number, because the mean of its divisors is an integer number (114997812930).

Almost surely, 2^{21130044431040} is an apocalyptic number.

21130044431040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21130044431040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (38639265144480).

21130044431040 is an abundant number, since it is smaller than the sum of its proper divisors (56148485857920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21130044431040 is a wasteful number, since it uses less digits than its factorization.

21130044431040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5561 (or 5548 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 21130044431040 its reverse (4013444003112), we get a palindrome (25143488434152).

The spelling of 21130044431040 in words is "twenty-one trillion, one hundred thirty billion, forty-four million, four hundred thirty-one thousand, forty".