Search a number
-
+
211301000103 = 3143948946259
BaseRepresentation
bin1100010011001010000…
…1010110001110100111
3202012101221002222020210
43010302201112032213
511430221024000403
6241023105430503
721160143603114
oct3046241261647
9665357088223
10211301000103
11816809a6906
1234b5033b433
1316c0570489b
14a326d4590b
15576a66db03
hex31328563a7

211301000103 has 8 divisors (see below), whose sum is σ = 281930457600. Its totient is φ = 140769438008.

The previous prime is 211301000101. The next prime is 211301000123. The reversal of 211301000103 is 301000103112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 211301000103 - 21 = 211301000101 is a prime.

It is a super-2 number, since 2×2113010001032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211301000101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24468813 + ... + 24477446.

It is an arithmetic number, because the mean of its divisors is an integer number (35241307200).

Almost surely, 2211301000103 is an apocalyptic number.

211301000103 is a deficient number, since it is larger than the sum of its proper divisors (70629457497).

211301000103 is a wasteful number, since it uses less digits than its factorization.

211301000103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48947701.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 211301000103 its reverse (301000103112), we get a palindrome (512301103215).

The spelling of 211301000103 in words is "two hundred eleven billion, three hundred one million, one hundred three", and thus it is an aban number.

Divisors: 1 3 1439 4317 48946259 146838777 70433666701 211301000103