2113012113 has 4 divisors (see below), whose sum is σ = 2817349488. Its totient is φ = 1408674740.

The previous prime is 2113012087. The next prime is 2113012147. The reversal of 2113012113 is 3112103112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2113012113 - 2¹² = 2113008017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2113012092 and 2113012101.

It is not an unprimeable number, because it can be changed into a prime (2113012183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352168683 + ... + 352168688.

It is an arithmetic number, because the mean of its divisors is an integer number (704337372).

Almost surely, 2^2113012113 is an apocalyptic number.

It is an amenable number.

2113012113 is a deficient number, since it is larger than the sum of its proper divisors (704337375).

2113012113 is an equidigital number, since it uses as much as digits as its factorization.

2113012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 704337374.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 2113012113 is about 45967.5114945327. The cubic root of 2113012113 is about 1283.2186479550.

Adding to 2113012113 its reverse (3112103112), we get a palindrome (5225115225).

Subtracting 2113012113 from its reverse (3112103112), we obtain a palindrome (999090999).

The spelling of 2113012113 in words is "two billion, one hundred thirteen million, twelve thousand, one hundred thirteen".