Base | Representation |
---|---|
bin | 110000000010110110101110… |
… | …010111110101001011001011 |
3 | 1000201011022111202120222221112 |
4 | 300002312232113311023023 |
5 | 210143434334433402021 |
6 | 2025222555202400535 |
7 | 62336045143306223 |
oct | 6002665627651313 |
9 | 1021138452528845 |
10 | 211302431544011 |
11 | 61366948a66565 |
12 | 1b8479b096014b |
13 | 90b99701c3172 |
14 | 3a2714120d083 |
15 | 19666db60ed5b |
hex | c02dae5f52cb |
211302431544011 has 2 divisors, whose sum is σ = 211302431544012. Its totient is φ = 211302431544010.
The previous prime is 211302431543909. The next prime is 211302431544047. The reversal of 211302431544011 is 110445134203112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211302431544011 - 242 = 206904385032907 is a prime.
It is a super-2 number, since 2×2113024315440112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211302433544011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105651215772005 + 105651215772006.
It is an arithmetic number, because the mean of its divisors is an integer number (105651215772006).
Almost surely, 2211302431544011 is an apocalyptic number.
211302431544011 is a deficient number, since it is larger than the sum of its proper divisors (1).
211302431544011 is an equidigital number, since it uses as much as digits as its factorization.
211302431544011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 211302431544011 its reverse (110445134203112), we get a palindrome (321747565747123).
The spelling of 211302431544011 in words is "two hundred eleven trillion, three hundred two billion, four hundred thirty-one million, five hundred forty-four thousand, eleven".
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