211302431544047 has 2 divisors, whose sum is σ = 211302431544048. Its totient is φ = 211302431544046.

The previous prime is 211302431544011. The next prime is 211302431544049. The reversal of 211302431544047 is 740445134203112.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211302431544047 - 2¹⁶ = 211302431478511 is a prime.

It is a super-2 number, since 2×211302431544047² (a number of 29 digits) contains 22 as substring.

Together with 211302431544049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 211302431543995 and 211302431544013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211302431544049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105651215772023 + 105651215772024.

It is an arithmetic number, because the mean of its divisors is an integer number (105651215772024).

Almost surely, 2^{211302431544047} is an apocalyptic number.

211302431544047 is a deficient number, since it is larger than the sum of its proper divisors (1).

211302431544047 is an equidigital number, since it uses as much as digits as its factorization.

211302431544047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 322560, while the sum is 41.

Adding to 211302431544047 its reverse (740445134203112), we get a palindrome (951747565747159).

The spelling of 211302431544047 in words is "two hundred eleven trillion, three hundred two billion, four hundred thirty-one million, five hundred forty-four thousand, forty-seven".