Base | Representation |
---|---|
bin | 11110101111111010101… |
… | …010010101001011110101 |
3 | 21111000002222220102122001 |
4 | 132233322222111023311 |
5 | 234104443242440112 |
6 | 4254414203135301 |
7 | 305442650366023 |
oct | 36577252251365 |
9 | 7430088812561 |
10 | 2113034343157 |
11 | 745150888911 |
12 | 2a162ab14531 |
13 | 1243485ab5aa |
14 | 743b2a59713 |
15 | 39e7169ec57 |
hex | 1ebfaa952f5 |
2113034343157 has 2 divisors, whose sum is σ = 2113034343158. Its totient is φ = 2113034343156.
The previous prime is 2113034343149. The next prime is 2113034343179. The reversal of 2113034343157 is 7513434303112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1978745809041 + 134288534116 = 1406679^2 + 366454^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113034343157 - 23 = 2113034343149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113034343197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056517171578 + 1056517171579.
It is an arithmetic number, because the mean of its divisors is an integer number (1056517171579).
Almost surely, 22113034343157 is an apocalyptic number.
It is an amenable number.
2113034343157 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113034343157 is an equidigital number, since it uses as much as digits as its factorization.
2113034343157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 37.
Adding to 2113034343157 its reverse (7513434303112), we get a palindrome (9626468646269).
The spelling of 2113034343157 in words is "two trillion, one hundred thirteen billion, thirty-four million, three hundred forty-three thousand, one hundred fifty-seven".
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