211304211303 has 4 divisors (see below), whose sum is σ = 281738948408. Its totient is φ = 140869474200.

The previous prime is 211304211233. The next prime is 211304211319. The reversal of 211304211303 is 303112403112.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 211304211303 - 2¹² = 211304207207 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 211304211303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211304211323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35217368548 + ... + 35217368553.

It is an arithmetic number, because the mean of its divisors is an integer number (70434737102).

Almost surely, 2^211304211303 is an apocalyptic number.

211304211303 is a deficient number, since it is larger than the sum of its proper divisors (70434737105).

211304211303 is an equidigital number, since it uses as much as digits as its factorization.

211304211303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70434737104.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 211304211303 its reverse (303112403112), we get a palindrome (514416614415).

The spelling of 211304211303 in words is "two hundred eleven billion, three hundred four million, two hundred eleven thousand, three hundred three".