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211307 = 375711
BaseRepresentation
bin110011100101101011
3101201212012
4303211223
523230212
64310135
71540025
oct634553
9351765
10211307
11134838
12a234b
1375245
1457015
1542922
hex3396b

211307 has 4 divisors (see below), whose sum is σ = 217056. Its totient is φ = 205560.

The previous prime is 211297. The next prime is 211313. The reversal of 211307 is 703112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211307 - 24 = 211291 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211291 and 211300.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 211307.

It is not an unprimeable number, because it can be changed into a prime (211007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2819 + ... + 2892.

It is an arithmetic number, because the mean of its divisors is an integer number (54264).

2211307 is an apocalyptic number.

211307 is a deficient number, since it is larger than the sum of its proper divisors (5749).

211307 is an equidigital number, since it uses as much as digits as its factorization.

211307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5748.

The product of its (nonzero) digits is 42, while the sum is 14.

The square root of 211307 is about 459.6814114145. The cubic root of 211307 is about 59.5622773770.

Adding to 211307 its reverse (703112), we get a palindrome (914419).

The spelling of 211307 in words is "two hundred eleven thousand, three hundred seven", and thus it is an iban number.

Divisors: 1 37 5711 211307