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21131000000011 = 111921000000001
BaseRepresentation
bin1001100110111111100011…
…01111111010111000001011
32202211002210201111102220001
410303133301233322320023
510232202242000000021
6112535240345143431
74310443610266126
oct463376157727013
982732721442801
1021131000000011
116807674685950
1224533b518ab77
13ba384c691285
14530a628bb3bd
152699ec142091
hex1337f1bfae0b

21131000000011 has 4 divisors (see below), whose sum is σ = 23052000000024. Its totient is φ = 19210000000000.

The previous prime is 21130999999997. The next prime is 21131000000039. The reversal of 21131000000011 is 11000000013112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21131000000011 - 25 = 21130999999979 is a prime.

It is a super-2 number, since 2×211310000000112 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21131000000111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 960499999990 + ... + 960500000011.

It is an arithmetic number, because the mean of its divisors is an integer number (5763000000006).

Almost surely, 221131000000011 is an apocalyptic number.

21131000000011 is a deficient number, since it is larger than the sum of its proper divisors (1921000000013).

21131000000011 is a wasteful number, since it uses less digits than its factorization.

21131000000011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1921000000012.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 21131000000011 its reverse (11000000013112), we get a palindrome (32131000013123).

The spelling of 21131000000011 in words is "twenty-one trillion, one hundred thirty-one billion, eleven", and thus it is an aban number.

Divisors: 1 11 1921000000001 21131000000011