Base | Representation |
---|---|
bin | 11110101111111110110… |
… | …000110010001000110101 |
3 | 21111000021210100211221001 |
4 | 132233332300302020311 |
5 | 234110113401042402 |
6 | 4254425101523301 |
7 | 305444444235034 |
oct | 36577660621065 |
9 | 7430253324831 |
10 | 2113103143477 |
11 | 7451866aa587 |
12 | 2a1649b73531 |
13 | 12435991a041 |
14 | 743bbc4871b |
15 | 39e77740187 |
hex | 1ebfec32235 |
2113103143477 has 2 divisors, whose sum is σ = 2113103143478. Its totient is φ = 2113103143476.
The previous prime is 2113103143441. The next prime is 2113103143493. The reversal of 2113103143477 is 7743413013112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1878678681201 + 234424462276 = 1370649^2 + 484174^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113103143477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113103143427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056551571738 + 1056551571739.
It is an arithmetic number, because the mean of its divisors is an integer number (1056551571739).
Almost surely, 22113103143477 is an apocalyptic number.
It is an amenable number.
2113103143477 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113103143477 is an equidigital number, since it uses as much as digits as its factorization.
2113103143477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42336, while the sum is 37.
Adding to 2113103143477 its reverse (7743413013112), we get a palindrome (9856516156589).
The spelling of 2113103143477 in words is "two trillion, one hundred thirteen billion, one hundred three million, one hundred forty-three thousand, four hundred seventy-seven".
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