211311012113 has 2 divisors, whose sum is σ = 211311012114. Its totient is φ = 211311012112.

The previous prime is 211311012097. The next prime is 211311012149. The reversal of 211311012113 is 311210113112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 186651649024 + 24659363089 = 432032^2 + 157033^2 .

It is a cyclic number.

It is not a de Polignac number, because 211311012113 - 2⁴ = 211311012097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211311012091 and 211311012100.

It is not a weakly prime, because it can be changed into another prime (211311002113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655506056 + 105655506057.

It is an arithmetic number, because the mean of its divisors is an integer number (105655506057).

Almost surely, 2^211311012113 is an apocalyptic number.

It is an amenable number.

211311012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211311012113 is an equidigital number, since it uses as much as digits as its factorization.

211311012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 211311012113 its reverse (311210113112), we get a palindrome (522521125225).

The spelling of 211311012113 in words is "two hundred eleven billion, three hundred eleven million, twelve thousand, one hundred thirteen".