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2113111103003 = 6175234604701
BaseRepresentation
bin11110101111111111001…
…111001001011000011011
321111000022100100020100022
4132233333033021120123
5234110122420244003
64254425544301055
7305444602005455
oct36577717113033
97430270306308
102113111103003
117451901466aa
122a165077178b
1312435b475c14
14743bcd1b2d5
1539e782b3738
hex1ebff3c961b

2113111103003 has 8 divisors (see below), whose sum is σ = 2148038226576. Its totient is φ = 2078193204000.

The previous prime is 2113111102961. The next prime is 2113111103011. The reversal of 2113111103003 is 3003011113112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2113111103003 - 210 = 2113111101979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2113111103603) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1843448 + ... + 2761253.

It is an arithmetic number, because the mean of its divisors is an integer number (268504778322).

Almost surely, 22113111103003 is an apocalyptic number.

2113111103003 is a deficient number, since it is larger than the sum of its proper divisors (34927123573).

2113111103003 is an equidigital number, since it uses as much as digits as its factorization.

2113111103003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4612285.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 2113111103003 its reverse (3003011113112), we get a palindrome (5116122216115).

The spelling of 2113111103003 in words is "two trillion, one hundred thirteen billion, one hundred eleven million, one hundred three thousand, three".

Divisors: 1 61 7523 458903 4604701 280886761 34641165623 2113111103003