2113111231041 has 4 divisors (see below), whose sum is σ = 2817481641392. Its totient is φ = 1408740820692.

The previous prime is 2113111231013. The next prime is 2113111231087. The reversal of 2113111231041 is 1401321113112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2113111231041 - 2¹⁰ = 2113111230017 is a prime.

It is a super-2 number, since 2×2113111231041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2113111230999 and 2113111231017.

It is not an unprimeable number, because it can be changed into a prime (2113111231841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352185205171 + ... + 352185205176.

It is an arithmetic number, because the mean of its divisors is an integer number (704370410348).

Almost surely, 2^{2113111231041} is an apocalyptic number.

It is an amenable number.

2113111231041 is a deficient number, since it is larger than the sum of its proper divisors (704370410351).

2113111231041 is an equidigital number, since it uses as much as digits as its factorization.

2113111231041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 704370410350.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 2113111231041 its reverse (1401321113112), we get a palindrome (3514432344153).

The spelling of 2113111231041 in words is "two trillion, one hundred thirteen billion, one hundred eleven million, two hundred thirty-one thousand, forty-one".