211311214011133 has 4 divisors (see below), whose sum is σ = 211715250749728. Its totient is φ = 210907177272540.

The previous prime is 211311214011113. The next prime is 211311214011223. The reversal of 211311214011133 is 331110412113112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211311214011133 - 2⁹ = 211311214010621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211311214011098 and 211311214011107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211311214011113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202018368513 + ... + 202018369558.

It is an arithmetic number, because the mean of its divisors is an integer number (52928812687432).

Almost surely, 2^{211311214011133} is an apocalyptic number.

It is an amenable number.

211311214011133 is a deficient number, since it is larger than the sum of its proper divisors (404036738595).

211311214011133 is an equidigital number, since it uses as much as digits as its factorization.

211311214011133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 404036738594.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 211311214011133 its reverse (331110412113112), we get a palindrome (542421626124245).

The spelling of 211311214011133 in words is "two hundred eleven trillion, three hundred eleven billion, two hundred fourteen million, eleven thousand, one hundred thirty-three".