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2113124312333 is a prime number
BaseRepresentation
bin11110110000000000000…
…001100010010100001101
321111000100021012100010202
4132300000001202110031
5234110134310443313
64254431135343245
7305445122202566
oct36600001422415
97430307170122
102113124312333
11745197649001
122a1655081b25
1312436111c4a8
14743c099916d
1539e79522558
hex1ec0006250d

2113124312333 has 2 divisors, whose sum is σ = 2113124312334. Its totient is φ = 2113124312332.

The previous prime is 2113124312219. The next prime is 2113124312339. The reversal of 2113124312333 is 3332134213112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1800757337929 + 312366974404 = 1341923^2 + 558898^2 .

It is a cyclic number.

It is not a de Polignac number, because 2113124312333 - 232 = 2108829345037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2113124312296 and 2113124312305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2113124312339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056562156166 + 1056562156167.

It is an arithmetic number, because the mean of its divisors is an integer number (1056562156167).

Almost surely, 22113124312333 is an apocalyptic number.

It is an amenable number.

2113124312333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113124312333 is an equidigital number, since it uses as much as digits as its factorization.

2113124312333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7776, while the sum is 29.

Adding to 2113124312333 its reverse (3332134213112), we get a palindrome (5445258525445).

The spelling of 2113124312333 in words is "two trillion, one hundred thirteen billion, one hundred twenty-four million, three hundred twelve thousand, three hundred thirty-three".