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2113130000323 = 18111674751383
BaseRepresentation
bin11110110000000000010…
…111001110111111000011
321111000100122220022121001
4132300000113032333003
5234110142240002243
64254431501312431
7305445221432626
oct36600027167703
97430318808531
102113130000323
1174519a883521
122a1656b65717
13124362361474
14743c1639dbd
1539e79c97a4d
hex1ec005cefc3

2113130000323 has 4 divisors (see below), whose sum is σ = 2124804751888. Its totient is φ = 2101455248760.

The previous prime is 2113130000309. The next prime is 2113130000353. The reversal of 2113130000323 is 3230000313112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113130000323 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2113130000323.

It is not an unprimeable number, because it can be changed into a prime (2113130000353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5837375511 + ... + 5837375872.

It is an arithmetic number, because the mean of its divisors is an integer number (531201187972).

Almost surely, 22113130000323 is an apocalyptic number.

2113130000323 is a deficient number, since it is larger than the sum of its proper divisors (11674751565).

2113130000323 is a wasteful number, since it uses less digits than its factorization.

2113130000323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11674751564.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 2113130000323 its reverse (3230000313112), we get a palindrome (5343130313435).

The spelling of 2113130000323 in words is "two trillion, one hundred thirteen billion, one hundred thirty million, three hundred twenty-three", and thus it is an aban number.

Divisors: 1 181 11674751383 2113130000323