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21131312401 = 59393558059
BaseRepresentation
bin10011101011100001…
…100011110100010001
32000112200021220010001
4103223201203310101
5321234103444101
613412501210001
71345440122533
oct235341436421
960480256101
1021131312401
118a64090851
124118a00901
131cb9b9ca64
141046655853
1583a239901
hex4eb863d11

21131312401 has 4 divisors (see below), whose sum is σ = 21134876400. Its totient is φ = 21127748404.

The previous prime is 21131312333. The next prime is 21131312417. The reversal of 21131312401 is 10421313112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21131312401 - 211 = 21131310353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21131312431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1773091 + ... + 1784968.

It is an arithmetic number, because the mean of its divisors is an integer number (5283719100).

Almost surely, 221131312401 is an apocalyptic number.

It is an amenable number.

21131312401 is a deficient number, since it is larger than the sum of its proper divisors (3563999).

21131312401 is an equidigital number, since it uses as much as digits as its factorization.

21131312401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3563998.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 21131312401 its reverse (10421313112), we get a palindrome (31552625513).

The spelling of 21131312401 in words is "twenty-one billion, one hundred thirty-one million, three hundred twelve thousand, four hundred one".

Divisors: 1 5939 3558059 21131312401