Base | Representation |
---|---|
bin | 11110110000000000011… |
… | …110111010011001001011 |
3 | 21111000100210200120122111 |
4 | 132300000132322121023 |
5 | 234110143243410011 |
6 | 4254432012403151 |
7 | 305445244515106 |
oct | 36600036723113 |
9 | 7430323616574 |
10 | 2113132013131 |
11 | 7451a0a287a7 |
12 | 2a16577764b7 |
13 | 1243628b7689 |
14 | 743c1a0173d |
15 | 39e7a044121 |
hex | 1ec007ba64b |
2113132013131 has 2 divisors, whose sum is σ = 2113132013132. Its totient is φ = 2113132013130.
The previous prime is 2113132013119. The next prime is 2113132013149. The reversal of 2113132013131 is 1313102313112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2113132013131 - 211 = 2113132011083 is a prime.
It is a super-2 number, since 2×21131320131312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2113132013731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056566006565 + 1056566006566.
It is an arithmetic number, because the mean of its divisors is an integer number (1056566006566).
Almost surely, 22113132013131 is an apocalyptic number.
2113132013131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113132013131 is an equidigital number, since it uses as much as digits as its factorization.
2113132013131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 2113132013131 its reverse (1313102313112), we get a palindrome (3426234326243).
The spelling of 2113132013131 in words is "two trillion, one hundred thirteen billion, one hundred thirty-two million, thirteen thousand, one hundred thirty-one".
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